[36tudordeluxe]

With fresh charge on battery, batt. shows 12.7V, 12.7V to starter solenoid and 12.7V to hot side of ignition switch, switch on cold side terminal shows 11.71V when switched on and 11.49V to positive side of coil and 9.8V across coil terminals due to internal resistor in coil. So question is: why am I getting nearly a full volt of drop across ignition switch when turned to the on position; I have disassembled and cleaned the contacts previously. Another curious thing is that when I flip the lever on the ignition switch to the on position it activates coil but when I turn lever to off position the coil still has power going to it, power does not completely go off until I turn ignition key to the off position.