Quote:
Originally Posted by Bret (OH)
The "I" wire sends 12 volts to the coil for starting.
There is a contact inside the solenoid that powers the "I" terminal with full battery voltage when the solenoid is engaged. That voltage by-passes the ballast resistor and allows for a more powerful spark to help with starting. Then, when the solenoid drops out, the coil receives reduced voltage through the ballast circuit.
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Never knew! Thanks..For some reason I thought the ballast took care of all of that.