Quote:
Originally Posted by G.M.
Old Henry I have . . . tested the flow of pumps . . .
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GM. I love what you've done. I am, perhaps, a bit more skeptical of opinions unsupported by actual scientific testing because of my profession (lawyer.) So, I really appreciate you taking the time to explain in detail the testing that you have done.
The resullts of your test seem to support the point that I was making - that moving the water through the block faster will cause a lower temperature of the water coming out of the top of the block because it had less time in the block to heat up. What would have been interesting in your testing would have been to measure the temperature of the water going into the block coming out of the bottom of the radiator to see whether it was, in fact, colder when the water was moving slower and hotter when it was moving through faster. I don't suppose you took that measurement. If so, I'd be interested in your data.
With the outlet temperature of the water being lower with faster water movement, that would also give the illusion, if not the reality, that the engine temperature was lower because the temperature guage actually measures the outlet temperature. Thus, moving the water faster with more efficient pumps would at least give the appearance, if not the reality, that the engine was running cooler.
Even though I suggested that, after a certain velocity of water going through the system is reached, higher velocity no longer cools any better without increasing the cooling efficiency of the radiator; it takes a little more "faith" to believe that at lower, i.e. stock, water velocity, the engine temperature is OK because the outlet temperature where the gauge reads will be higher. Thus, if for nothing more than just the peace of mind that comes from seeing the gauge read lower, it might be worth moving the water a little faster with more efficient pumps.
That is, in fact, what I have done. It wasn't intentional. It was just that the last pumps I bought from C&G were higher efficiency. It can't hoyt.
Thanks again for your patient explanation.